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NoetherianOperators :: eliminatingDual

eliminatingDual -- eliminating dual space of a polynomial ideal



Given a list of variable indices, compute the a basis for all dual elements orthogonal to I which have total degree in the variables on the list bounded by d.

i1 : R = CC[x,y];
i2 : I = ideal{x^2-y^3}

              3    2
o2 = ideal(- y  + x )

o2 : Ideal of R
i3 : eliminatingDual(origin R, I, {0}, 2)

o3 = | y5+x2y2 y4+x2y y3+x2 xy2 xy x y2 y 1 |

o3 : DualSpace

This function generalizes truncatedDual in that if v includes all the variables in the ring, then its behavior is the same.

i4 : eliminatingDual(origin R, I, {0,1}, 2)

o4 = | xy y2 x y 1 |

o4 : DualSpace

See also truncatedDual.


The space of dual elements satisying the conditions is not in general of finite dimension. If the dimension is infinite, this function will not terminate. This is not checked. To ensure termination, the local dimension of I at p should not exceed the length of v, and certain genericity constraints on the coordinates must be met.

Ways to use eliminatingDual :

For the programmer

The object eliminatingDual is a method function with options.